Now in the equation (½)x + 8 = 24½ we imagine that x represents an unknown
length. In the stick below, the top stick has length (½)x+8 while the bottom stick
has length 24½. The equation say both sticks have the same length, here 24½
Cutting off or subtracting 8 from both sticks gives
a stick of length (½)x on top and a stick of length 17 = 25 - 8 on bottom. This
second stick diagram represents the equation (½)x =17.
Now x = (½)x + (½)x and 16½ + 16½ = 33. So double or multiply by
two to get the diagrams
(½)x
|
(½)x
|
and hence
|
x
|
16½
|
16½
|
33
|
These stick diagram suggest that x =33. See check below.
A summary of the operation follow.
If I was solving (½)x + 8 = 24½
in class, I would just fill in the
table and skip the work above. Each table consists of a diagram in the
left column, a description of what is done or given in the middle column, and
the equivalent equations in the rightmost column. At the moment, you are
required to draw the stick diagram in the solution of the equation. That is a
crutch. Later on, only the equation column is required with a few words to
explain the operations.
| Stick Diagram |
Operation |
Equation |
|
|
Initial Situation
Given |
(½)x + 8 = 24½ |
|
|
Subtract 8
|
(½)x = 16½ |
|
|
Duplicate (a.k.a.
Replicate twice,
Multiply by 2, the
reciprocal of ½ |
(½)x + (½)x =
16½ +16½ |
|
|
Simplify
|
x = 33 |
Remember what we do one stick in a pair, we must do do the
other, to keep the lengths after the operation, the same. If two sticks
have the same length, we cut 5 from and 8 from the other, the resulting pair of
sticks will not the same the length. And if two sticks in a pair have the
same length, and I remove one half of one and two-thirds of the other, the
resulting pair will have different lengths.
Check:
Is x = 33 a solution of (½)x + 8 = 24½? Now
|
Left Hand Side |
= (½)x + 8
= (½)33 + 8
= 16½ + 8
= 24½ |
Right Hand Side |
= 24½ |
So both sides of the equation are equal when x = 33.
Note: We can always check whether a number is a solution of an
equation or not by computing the left and right sides of an equation for or at
that number. If the two sides differ, the number is not a solution.
- If you are asked to show that a number satisfies an equation you do the
check.
- If you are asked to find a solution to an equation algebraically you
should show some work (besides trial and error) that leads to the solution.
Then you should check the solution.
Solutions of equations can always be checked. So before you hand-in an
answer, you can always check whether it is correct or not. And if it is not
correct, you should say so if you do not have time to find the correct
answer. Instructors want to see how you obtain the solution. If your
arithmetic without a calculator is usually good, the odd error in your work is
not as important as you showing that you have master an algebraic method for
solving problems.
Example: (½)x + 4 = 8 (animated gif)
| Example: |
1
3 |
x |
+ 5 |
= |
12 (animated gif) |