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(i) x + 20 = 29 WS
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Solving Linear
Equations
(Feb 14, 2005)
with & then without stick diagrams plus   solving word problems; and solving systems: -  essentially one unknown, essentially triangular & general

 


Read them in order

(i) x + 20 = 29 WS
(ii) 2x + 6 = 24 WS
(iii) 3x + 10 = 32 WS
(iv) 5a + 16 = 3a+ 24 WS
(v)  (½)x + 8 = 24½ WS
(vi)  (¾)a + 16 = (¼)a+ 24 WS
(vii) (¾)q + 17 = 32 WS
(viii) 13 =[2/3]x +7 twice WS
(5/6)q + 8+(5/6) = 14 + (2/3) WS
Proper Use of Equal Sign



 

Introduction to Stick Diagrams

Our aim in introducing stick diagrams is to show how to understand and solve equations for unknown length or number x.  In the first example below we will go from a given value of x to a stick diagram constructed or implied by that value of x.  Then we will explore a few simple examples where we find the value of x from a stick diagram.  This is the simple and slow start of a longer story. So follow the story or chains of reason here because at the end of this story, I or we hope you will be able to solve equations in one and more unknowns, and beyond that, you will have a path for tutoring or leading others to this ability. So have patience.

Step 1. From value of x to one or more stick diagrams.

Step 2 below, going the other way, is more important.

Suppose x represents the length of a stick of length 15.  We will write x = 15. We draw two parallel sticks to represent this situation in a geometric manner.

x

15

The equation x = 15 implies x +5 = 20. We can draw the following to represent

x
5

20

this equation or situation x + 5 = 20. 


The foregoing shows how we can go from a value of x to an equation in x and a stick diagram which describes that equation.  That is step 1 in our journey.


Step 2. From a Stick Diagram to a value of x, or finding an unknown length from a stick diagram.

Imagine we are given  x + 4 = 16 for an unknown length x. We want to find x. To that we describe the equation by the stick diagram.

x
4

16

This diagrams indicates a stick of length x + 4 has the same length as a stick of length16.  Now observe 16 -4 = 12  or 12 + 4  = 16. 

x
4

16

<---     12     ---> <---   4  -->

We are almost done.  Now  shorten the top and bottom sticks by 4 units. This cutting off or subtraction of 4 units gives the diagram

x

12

and suggests x = 12.  Let us check this suggestion.

Check:  When x = 12 (or when x is replaced by 12)

x + 4 = 12 + 4 = 16

as requested.

So x = 12 is a solution of x + 4 = 16. 

Another Examples of Step 2. Finding an unknown length from a stick diagram.

Suppose x is a length which satisfies solve x + 8 = 28.

x
9

29

 Find the length x with the aid of stick diagrams.

Stick Diagram Operation Equation
 
x
9

29
Given x +9 = 29
 
x
9

29
20 9
Preparation
for a subtraction
observe

29 - 9 = 20
or

29 = 20 + 9

 

 
x


20
Subtract 9 x + 9 = 29
      9 = 9     _
x       =  20

Conclusion: Must have x = 20

 If  I was solving 2x + 5 = 20 in class, I would just fill in the table and skip the work before it.  Each table consists of a diagram in the left column, a description of what is done or given in the middle column, and the equivalent equations in the rightmost column.  At the moment, you are required to draw the stick diagram in the solution of the equation. That is a crutch.  Later on, only the equation column is required with a few words to explain the operations.

Let us check this suggestion.

Check:  When x = 20 (or when x is replaced by 20)

x +9 = 20 + 9 = 29

So the conclusion x = 20 works.

 

 

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