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Many Equations with Essentially One Variable

Example:  Suppose the letters A, B, C and T satisfy the four equations

A = 2T
B = 3T
C = 4T and   
T + A + B + C = 60

That means A has the same value in the first and fourth equation, and so on. Now we use the first three equations 

A = 2T
B = 3T
C = 4T

to replace the A, B and C in the fourth equation

T + A + B + C = 60

That gives

T + 2T + 3T +4T = 60  

In other words  

10 T = 60

from which we get T = 6.  The first three equations by substitution now give

A = 2T = 2*6 = 12
B = 3T = 3*6 = 18
C = 4T = 4*6 = 24

Check:  we expect A =12, B = 18, C = 18 and T=6 to satisfy the original equations

A = 2T
B = 3T
C = 4T and   
T + A + B + C = 60

The first three are satisfied by the way in which computed A, B and C from T while  T + A + B + C = 6 + 12 + 18 + 24 = 60 by direct addition in your head, or if need-be, shame on you, with a calculator.

Remark: The fourth equation T + A + B + C = 60 is essentially an equation only in T because the other amounts A, B and C can be expressed in terms of T and thus eliminated by replacement or substitution in the fourth equation. Because the system 

A = 2T
B = 3T
C = 4T and   
T + A + B + C = 60

gives or reduces almost immediately a single equation in the one unknown T to solve, we say this is an essentially one variable system.  We can go further. See the next example.

First Animated Example

 

Exercise (1) :  Solve the essentially one variable system

A = 3T+ 8
B = T+ 4
C = ½T 
D = 2 T - 12 and   
T + A + B + 4C + D  = 100

and check your answers.

The values of the unknown T may be a positive or negative proper or improper fraction, or zero. ( I do not know. I have not solved this system. I have only written it.)

Teachers: The replacement of C by ½T in the last equation forces the calculation of 4(½T) and a formal, but more likely informal, application of the associative law for arithmetic with rational or real numbers

Second Animated Example 

Teachers: Substitutions or replacement in the above examples requires formal, but more likely informal, mastery of the distributive law.

Third Animated Example 

 

Solving Linear
Equations
|(Feb 14, 2005)
with & then without stick diagrams plus testing solutions -do not hand-in untested solutions;  solving word problems; and solving systems: -  essentially one unknown, essentially triangular & general

Skill in arithmetic with fractions is a must for algebra. 

Folder Chapters -
lesson groups

Proper Use of Equal Sign
A. Letters and Lengths
B.. Solving Linear Eq'ns - WS
C. Solving Linear Eq'ns - No Sticks
D. Almost One
E: 2D Systems - Sub Method.
E:  Continued
E: Still More
F. Larger Systems


Area Intro
(i) x + 20 = 29 WS
(ii) 2x + 5 = 20 WS
(iii) 3x + 10 = 32 WS
(iv) 5a + 16 = 3a+ 24 WS
(v)  (½)x + 8 = 24½ WS
(vi)  (¾)a + 16 = (¼)a+ 24 WS
(vii) (¾)q + 17 = 32 WS
(viii) 13 =[2/3]x +7 twice WS
(ix) Animated Examples WS
(a) Integral Coefficients (A)
(b) Integral Coefficients (B)
(c) Fractional Coefficients
(d) With parameters


Up
Proper Use of Equal Sign
A. Letters and Lengths
B.. Solving Linear Eq'ns - WS
C. Solving Linear Eq'ns - No Sticks
D. Almost One
E: 2D Systems - Sub Method.
E:  Continued
E: Still More
F. Larger Systems
 



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