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||Définition d'une variable || Algèbre || Arithmetique || Logique ||La raison basée sur les règles et modelés||

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1,  Elements of Reason.
1A. Pattern Based Reason 
1B. Math Curriculum Notes
2. Three Skills for Algebra
   Three Skills for Algebra
3. Why Slopes & More Math
 Avid Readers: Try Pattern Based Reason  & chs 
 1 to 12, 14,  16 & 17  in  Three Skills for Algebra.
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6. Number Theory
7. Calculus Introduction
8. Complex Numbers 
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14. Algebra, Odds & Ends, Etc
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17. Math Education Essays
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2. Algebra Starters 
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5. More Geometry
6. Calculus Modifiers 
7. Multiple Logics in Maths
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YOU are better than YOU think. Show yourself  how:  

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Read  logic chapters 1 to 5  in online volume Three Skills for Algebra  for greater skills & confidence in  work 
and study.

Learn to read notes and textbooks like a lawyer, so that no nuance, no subtlety and no clause escapes your attention.

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 Logic chapters 1 to 5  re- appear not in sequence, as is or longer,  in  Volume 1A,  Pattern Based Reason, Bon Appetite.

Logic Mastery
 Amazing, Amusing, Amorous,  Delicious, Delightful, Edifying, Strengthening Elixir. 
It eases work & learning difficulties Makes the hard easier. Opens eyes. Leads to greater precision.
in reading and
writing

Logic mastery makes the hard, easier. Logic mastery  leads to better, stronger and richer comprehension.  Logic mastery  improves reading and writing.  Logic mastery ease learning difficulties.  Logic mastery gives a headstart.  In sum, logic mastery  will develops critical thinking, improve reading and writing, and give a firmer base for work and studies at many levels. Good luck.


After logic  (a) continue reading Three Skills for Algebra, chapters 8 to 14  and do so alongside site area on solving liinear Equations ; or (b) see this calculus starter lesson and Volume 3, Why Slopes  & More Math, chapters 2 to 6;

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Caution: Site advice is approximately correct, for some circumstances, not all. That leaves room for thought

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What may be learnt and when depends on how skills and concepts are developed. Making the hard easier and clearer will allow earlier & richer development of skills and concepts.


Try the Twiddla Whiteboard. In principle, it  allows to people to draw and chat together online on a copy of this webpage or a clean sheet. The chat may be via text or audio.  Visit www.twiddla.com to set up whiteboards to work with the webpage of your choice.

For online automated help in senior high school maths & calculus, visit  quickmath.com  For Automatic Calculus and Algebra Help with derivatives, integrals, graphs, linear equations, matrix algebra, visit calc101.com  With  overlap, each site quickmath & calc101offers a different range of services, some free, some not, all based on webmathematica. Good luck.

More About Real Numbers

Division of Real Numbers

When a and b are nonzero unsigned numbers, decimal arithmetic tells us how to compute the quotient  a/b. Decimal arithmetic also says how to compute the reciprocal 1/b, another unsigned number.  Here 1/b denotes the result of 1 divided by b.    The latter reciprocal has the property  b  (1/b) = (1/b) b = 1.   Division by zero is not defined.

In decimal arithmetic,

a/b = (a)(1/b)

As the proof of this property belongs to a rigorous discussion of arithmetic, we assume it instead.

Assumption A8:    If a and b are unsigned numbers > 0,  then  division of a by b gives the same result as multiplying a by the reciprocal (1/b) of the divisor b.

a/b = (a)(1/b)

So  division by an nonzero b > 0 can be replaced by multiplication by its reciprocal 1/b. This allows multiplication rules or properties of arithmetic to be applied in calculations where there is division.  The latter can be replaced by multiplication by a reciprocal.

Assumption A5: If a and b are unsigned numbers, the decimal computation of  the reciprocal  of the unsigned number (a/b)    yields the same result as

The reciprocal of a quotient.

If b and c are unsigned numbers with 1 = bc  then multiplication by (1/b) implies

                             (1)(1/b) = (1/b) (bc)

Therefore   1/b = (1/b)(bc) = ( (1/b) b) c = 1c = c.   Therefore reciprocal of an unsigned b may be found without further computation if   there is a number c with bc =1. From this conclusion, we may obtain a formula for the reciprocal of a quotient (a/b) when the numerator a and the denominator b are both nonzero.

From above  (a/b) = a (1/b) while  (b/a) = b (1/a). Therefore

   (a/b)(b/a) = {a(1/b)} {b(1/a)} by replacement of equals

                   = a { (1/b) {b(1/a)}  } by the associative property for multiplication

                  =   a { { (1/b) b } (1/a) }  by the associative property again

                 = a  { 1 (1/a))  as   (1/b) b = 1

                 = a (1/a)     as 1 d = d for any unsigned number d

                = 1 

The foregoing indented material implies  (a/b) and (b/a) are reciprocals of each other in the sense the 1 divided by the quotient a/b gives the same result as b/a. This conclusion should agree with what you have learnt previously about fractions. 

Assumption A9: If a and b are nonzero unsigned numbers > 0 then    [1 divided by (a/b)]  =  b/a

Exercise: Use the commutative law for multiplication to   show  (1/b)(1/c)(bc) = 1 when b and c are nonzero unsigned numbers.  Then compute (1/bc)  -  (1/b)(1/c).

Division of Real Numbers:

The foregoing handles the division with unsigned numbers.

When a and b are both positive,  the quotient a/b =  a (1/b). Here the quotient a/b and  the reciprocal1/b  may be computed using decimal arithmetic.

When a and b are not both positive, and both are nonzero, we may assume

a = sign(a)p and b = sign(b) p

where p and q are positive.  Here the quotient p/q and the reciprocal1/q can be computed with decimal arithmetic.  When a and b are positive, we perversely observe  a/b = p/q = { (1)/(1) }(p/q)

Now when a and b are not both positive, put

a/b  =   (sign(a)/sign(b)) (p/q)                   

with the convention that

(1)/(-1) = -1 =   (-1)/(1)           and (1)/(1) = 1= (-1)/(-1)

This computation rule defines multiplication of real numbers with signs. The formula a/b  =   (sign(a)/sign(b)) (p/q)  also hold when a and b are unsigned numbers > 0.

Exercise: Show  1/sign(b) = sign(b)

Assumption A10 (Computation Rule):  if  a = sign(a)p and b = sign(b) p with p > 0 then

a/b  =   (sign(a)/sign(b)) (p/q)

With this computation rule, put 1/b =  (1/sign(b)) (1/q).    This agrees with the previous definition when sign(b) = 1. Division by zero remains undefined.  Try the following exercises  with the foregoing computation rule for quotients a/b


Exercise: Show  a/b = a (1/b) when a and b are real numbers with b nonzero.
Exercise: Show  (a/b)(c/d) = (ab)/(cd) when when a, b, c and d are real numbers with b and d  nonzero.
Exercise: Show  (ac/bc) = a/b when when a, b and c are real numbers with b and c  nonzero.
Exercise: Show the reciprocal of (a/b) is still (b/a) when a and b are real numbers, both nonzero.
Exercise: For a nonzero b = sign(b) q, the number c =  sign(b) (1/q)   has the property that bc = 1 Show if d and c appear to be two numbers with bc = 1 and bd = 1 then d = c.  

The expression of division in terms of multiplication  allows rules for arithmetic (the equality of calculations) to avoid the discussion or mention of division.

Addition and Subtraction of Unsigned Numbers

When a and b are both unsigned number, or both positive, decimal arithmetic says how to compute a + b.  Decimal arithmetic also says how to compute a - b when a > b. Comparison of decimal expansions determines when a > b, a = b and a < b.

On a coordinate line,  a + b may be represented by a steps of one unit to the right of the origin followed by b further steps of one unit. If a and b are represented by vectors of length a and b respectively, with tails at the origin, you may visualize this addition in terms of the parallelogram law (slightly squashed).

In the case a > b,  we may compute c = a - b by decimal arithmetic.   The result c > 0  has the property  a = b + c.

Example 1. In the case where a and b are whole numbers with a   > b, think of two situations.

  1. You have  a pennies in bottle, and want to spend b pennies.
  2. You have b pennies in a bottle, and want to spend a pennies.

In the first case 1, the inequality  a > b allows you to take or subtract b pennies from the a in the bottle with a remainder of  c = a - b pennies.

In the second case 2, you may take all the b pennies in the bottle for your spending plans, but there will be a shortage of c = a - b pennies for those plans.  Further subtraction of pennies from the bottle is impossible.  Examples like case 2 this led people to say that negative numbers were imaginary.

Example 2. In the case where a and b are unsigned numbers with a   > b  > 0, think of two situations.

  1. You have  moved a units to the right of the origin on a coordinate line,  and want to move b units to the left.
  2. You have  moved b units to the right of the origin on a coordinate line,  and want to move a units to the left.

In the first case 1,  a > b and c = a - b implies a = c + b.    Therefore subtraction of b units from a units leaves you c =  a - b units to the right of the origin. Here subtraction of b units means b movement to the left.

In the second case,  a > b and c = a - b implies a = b + c as before. To move a = b + c units to the left of b on the coordinate line, first b movements to the left and then move a further c units. This leaves you c units to the left of the origin at a point with coordinates - c. This point represents the result of "taking" a = b +c units from b units. 

Exercise: Express the calculation in examples 1 and 2 with vectors drawn on or parallel to a coordinate line.

Assumption A11 (A computational Rule for subtraction of unsigned numbers).   If a > b, then   c = a - b may be computed by decimal arithmetic, and we may put  b - a = -c  = (-1) c

Addition and Subtraction of Signed Numbers.

Successive movement along a coordinate line may be described in terms of vectors or distance & direction traveled. This viewpoint gives a vectorial framework for describing and explaining the addition and subtraction of real numbers.

Suppose  a = sign(a)p and b = sign(b) p with p > q then   a is farther from the origin than b.  We consider four cases

  sign(a) = 1 sign(a) = -1
sign(b) = 1 Movement in same direction 
a + b = p + q
a = p and b = q
Movement in opposite direction.
Compute c = p-q. Then a +b = -c

a = -p and b = q

sign(b) = -1 Movement in opposite direction.
a + b = p - q
a = p and b = -q
Movement in same direction 
Compute c= p+q. Then a+ b = -c
a = -p and b = -q

Exercise: Draw all four cases and illustrate them with vector addition.(or come for more details to appear when I have the time and patience)

With the above definition, if a = sign(a)p and b = sign(b) p, then we put -b = (-1) b and we put a - b = a + (-b).

The expression of subtraction in terms of addition allows rules for arithmetic (the equality of calculations) to avoid the discussion or mention of subtraction.

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Complex Numbers

Hint: See the (newest) Complex Number. Starter Lesson for a simple geometric introduction, then continue with easy consequence below.

The fundamental theorem of algebra and partial fraction decomposition in calculus depend on complex numbers.  

Easy Consequences
Vec & Cmplx  No Applet
B2 C. Conjugates
B3 Pythagoras
B4 Distance
B5 Rt Triangle Similarity
B6 Trig., Functions
B7 Dot & Cross Products
B8 Cosine Law
B9 Exponential & cis fns
B10 Easy Trig Identities
B11 Set Viewpoint
Links: Interactive Maths
 

First Earlier (Old) exposition of complex numbers follows in Z1 to B1 below -  read for review or revision .

First (Old) Complex No Intro
Distributive Law
A1 Add Poiints
A2 Polar Coords
A3 Polar Multiply
A4 Complex No.s
A5 Real Numbers
A6 Law of Signs
A7 Key Properties
B1 2nd Mult Method
C1 Unsigned Coords
C2 Signed Coords
C3 Set Codification
C4 More On Real No.s
D1 Arrow Navigation
D2 Sum of Motions
D3 Addition Method I
D4 Addition Method II
D5 Addition Method III
D6 Coordinate Addition
D7 1st Distributive Law
D8 2nd Distributive Law
D9 3rd Distributive Law

D1 to  D6 after provide a review of vectors.

More on Complex Numbers:

Chapters in Volume 3::
19 Logs & Powers
19 Natural Log.
19 Exponential Fn.
20 What's Next
21 Add Vectors
22 Complex #'s
23 Complex #'s
23 Trig Identity
23 Proofs of.
24 Complex Logs etc

This further  Complex Number
  Intro
assumes the field properties
of real numbers in place of
deriving them geometrically



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