Algebraic (Exponential and Logarithmic) Theory
of powers and roots
This page derives the theory of radicals and exponents from
algebraically described properties of the natural logarithms and exponential
function. Student may assume calculator buttons provide the values of
the latter.
A full development of theory or natural logarithms and the
exponential appears in calculus books. This site provides its version of that
development in chapter 19 of Volume 3, Why
Slopes & More Math. Chapter 19 is included in webpages 19 Logs & Powers
19 Natural Logarithms.
19 Exponential Function.
Optional readings, challenging perhaps, for now and later.
Hint: Assume the properties properties of the natural logarithms and exponential
function first and see their derivation later.
Natural logarithm and exponential functions with the aid of an electronic
calculators
Calculator button exercises met above suggest relationships between x2
and x3 buttons, the ax or yx
functions, and how to obtain ax = exp(x ln(a)) via a sequence
of operations on the calculator. The latter requires a > 0 but allows x to be
any real number. In the case of the natural e, ln(e) = 1 and ex
= exp(x ln(e)) = exp(x). So we can use the ex button on
the calculator to compute exp(x). The latter function should not be
confused with the EXP button present on some calculators.
A. Natural Logarithms:
The following properties can be illustrated or confirmed with an
electronic calculator.
- ln(x) is defined only when x > 0 and not defined when x < 0.
- Fundamental Properties of Logarithms:
ln(ab) = ln(a) + ln(b)
when a > 0 and b > 0.
- ln(1) = 0 from fundamental property or from a calculator.
- ln (1/a) = - ln(a)
- ln(an ) = n ln(a) for each whole number - demonstrate with
numbers and even proofs for small values of n.
- ln(1/an ) = -n ln(a) for each whole number n as ln(1/b) =
ln
B. Exponential Function
The existence of the exponential function exp(x) can be assumed, and then
computed with the aid of the ex button on a calculator.
Alternatively, the points on the graph of y = ln(x) can be plotted and
interpolated. Then exp(c) can be defined as the value of the
x-coordinate of the intersection of the horizontal line y = c with the graph y
= ln(x). The latter gives an example of the horizontal line method for
calculating a function or defining an inverse function. The use of this
horizontal line method to calculate exp(c) and the use of the vertical line
method to calculate ln(d) gives a pair of operations or functions, each of
which reverses the other. The formal definition of iverse function can
be skipped or included here. .
Main Properties
The following properties can be derived from the properties of the natural
logarithm and the horizontal line method for defining exp(x) from the graph of y
= ln(x). Alternatively some or all properties can be assumed without
proof, and the rest, if any, derived from the assumed ones. In either case
numerical examples are needed to empirically illustrate all the following
properties.
- Domain: exp(x) = ex is defined for all real numbers x,
at least those we can enter into the display of an electronic calculator
- Fundamental Property of Exponentials:
exp(a+b) = exp(a) * exp(b).
- exp(0) = 1
- exp(x) exp(-x) = 1 or exp(-x) = 1 / exp(x)
- ln(exp(x)) = x when x is real - so the natural log function ln reverses
the calculation of the exponential function exp (x),
- exp(ln(x)) = x when x > 0 - so exponential function exp reverses
the calculation of the natural log function ln(x),
C. Powers with whole number exponents
If we put fa(n) = exp(n ln(a)) then deriving the
following
fa(1) = a1
fa(2) = a2
fa(3) = a3.
fa(4) = a4.
or demonstrating these patterns numerically suggests the general
pattern f(n) = an or
an = exp(n ln(a))
for whole numbers n. The property exp(-x) = 1/exp(x) then implies
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D. Powers with real number exponents
Saying how to compute a number, defines it.
Suppose a is a positive number and x is a real number. Then compute the
power ax by the formula
ax = exp(x ln(a))
In the power ax the number a > 0 is called the
base and x is
called the exponent.
Two properties ax ay = ax+y
and (ax)y = axy can be
also suggested and verified in numerical exercises. Details of how these
algebraically described properties follow from the algebraically described properties of the exponential function and natural
logarithms follow.
| Derivation of ax+y = ax ay
ax+y = exp((x+y) ln(a)) by definition of ax+y
= exp(x ln(a) + y ln(a)) by distributive law
= exp (x ln (a)) exp(y ln(a))
due to fundamental property:
exp( c + d) = exp (c) exp(d)
for all real numbers c and d.
= ax ay by definition of ax
and ax
Derivation of (ax)y = axy
(ax)y = exp( y ln (ax))
= exp( y ln ( exp [ x ln(a ) ] )
= exp( y [x ln(a)] )
= exp( [yx] ln(a) )
= exp ( [xy] ln(a) ) = axy
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E. m-th Roots (m whole) for positive real numbers
Suppose a is a positive number, and m is a whole number.
Assume a = 64 and m = 2 on first reading. Then
assume a = 64 and m = 3 on second reading.
We will try to solve the equation
ym = a
for y where y is a positive number.
Solution: The natural logarithm of both sides of the equation ym
= amust be equal since ym and a are two different ways of
writing or representing the same number on paper. Therefore
ln(ym ) = ln(a)
But the left side ln(ym ) = m ln (y) due to the
fundamental property ln(pq) = ln(p) + ln (q) of natural logarithms when p and q
are positive. Therefore
m . ln(y) = ln(a)
The latter implies

and so

That is

should satisfy
ym = a
The m-th root of a is

F. Even Roots of Real Numbers
Saying how to compute a quantity defines it.
Recall a positive times a positive is positive,
zero times zerio is zero and negative times a negative is positive. Therefore x
2 > 0 for all real numbers x.
Square Roots
Because x 2 > 0 for all real
numbers x, the equation
x 2 = a
only has solutions x when a > 0, that is only when a
is non-negative. Defining
as the nonnegative real solution of x 2 = a
works only if a is positive or zero. For a = 0,
For a > 0, the solution is
provided by the computation

See above. The latter is called the principal or positive
square root. The negative square root is obtained by taking the negative of the
principal square root. It is given by

All Further Even Roots
Similarly, if n = 2m > 0 is an even whole number, then x
n = x 2m = xm x m >
0 for all real numbers x. Thus the equation
x 2m = a
only has a solution x when a > 0, that is only when a
is non-negative, since x 2m = xm x m >
0 for all real numbers x. The solution x = 0 when a = 0.
For a > 0, the positive
solution, called the principal root, is

There is also a negative solution

G. Odd Roots of Real Numbers
Saying how to compute a quantity defines it.
The identify x = sign(x) |x| and consequences
Each real number x = sign(x) |x|. For instance
-
+5 = (+1) 5 as sign (5) = +1 and |+5| = 5 = distance of +5 =
5 to origin 0
-
-4 = (-1) 4 as sign (4) = -1 and |-4| = 4 = distance of -4
to origin 0
-
0 = (0)(0) as sign(0) = 0 and |0| = 0 = distance of 0 to
itself.
Now sign(x) = +1, 0 or -1. In all, three cases [sign(x)]2 =
1. Therefore
x3 = [sign(x)]|x|3
In general,
x2m+1 = [sign(x)]|x|2m+1
since (+1)2m+1 = +1 and (-1)2m+1 = -1.
Cube Roots
For a in nonzero, the equation x3 = a
implies or requires
|y|3 = |a|
Therefore

When a is positive, taking y = |y| implies
y3 = |a| = a.
But when a is negative, taking y = (-1)|y| gives
y3 =(-1)3 |y|3 = - |a| = a.
The foregoing is equivalent to saying

satisfies y3 = a whenever a is nonzero. For a
non-zero, that is a > 0 or a < 0, let

and let

All further Odd Roots:
For a in nonzero, and n a whole number,
the equation x2n+1 = a implies or requires
|y|2n+1 = |a|
Therefore

When a is positive, taking y = |y| implies
y2n+1 = |a| = a.
But when a is negative, taking y = (-1)|y| gives
y2n+1 =(-1)2n+1 |y|3 = - |a| =
a.
The foregoing is equivalent to saying

satisfies y2n+1 = a whenever a is nonzero. For
a > 0 and a < 0
For a non-zero, that is a > 0 or a < 0, let

and let

Exercise: Sketch the graph of y = x3 for
-2 < x < 2. The equation x3 = b has
one and only real solution real solution as the horizontal line y = b intersects
the graph of y = x3 at most one point. According to the theory above,
for each nonzero real number b let b1/3 and

is the real solution of x 3 = b. Let

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