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Triangle Inequality |x +y| < |x| +|y|The following diagrams illustrate and imply the triangle inequality in for real numbers and for points in the plane. Geometric View in one dimensionEvery real number x and y can be identified with a displacement, arrow, vector or directed line segment.
The length of x + y that is |x+y| equals the sum of the lengths |x| and |y| when x and y have the same direction. The length of x + y that is |x+y| equals the difference of the lengths |x| and |y| when |x| > |y|.
Therefore |x| > |y|
Likewise when |y| > |x|
So in both cases
Geometric View in Two DimensionsEvery point x and y in the plane can be identified with an displacement, arrow or vector. When |x| > |y| and |y| = r > 0, the length L = |x+y| of of x+y satisfies
or equivalently
Likewise when |y| > |x|
So in both cases
Remark: The explanation or image in three dimensions is similar: Remark: When |x| > |y| >0 equality may hold in exactly one of the two inequalities
only when x and y are collinear. Remark: Algebraic proofs dependent on the Pythagorean distance formulas for the distance between points and for the lengths of vectors are available. Students of pure mathematics will or should see them. |
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To Learn More, visit Volumes 2 and 3. Advanced Topics
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